What is the limit as x approaches 0+of (sin(x^2))/x ?

The limit as x approaches 0+of (sin(x^2))/x is 0

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limit as x approaches 0+of (sin(x^2))/x

x \to 0 + lim (\frac{sin ( x ^{2} )}{x})

0

Solution steps

x \to 0 + lim (\frac{sin ( x ^{2} )}{x})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{cos ( x ^{2} ) \cdot 2 x}{1})

= x \to 0 + lim (\frac{cos ( x ^{2} ) \cdot 2 x}{1})

Plug in the value

x = 0

= \frac{cos ( 0 ^{2} ) \cdot 2 \cdot 0}{1}

Simplify

\frac{cos ( 0 ^{2} ) \cdot 2 \cdot 0}{1} : 0

= 0

\frac{d y}{d x} - 2 x y = e^{x^{2}}

x (\frac{d y}{d x}) + y = y^{2}

\int \frac{3 - 18 x}{64 - 9 x ^{2}} d x

\frac{d y}{d x} = \frac{b ^{2} x}{a ^{2} y}

\frac{\partial}{\partial x} (e^{2 x} + y ln (x))

What is the limit as x approaches 0+of (sin(x^2))/x ?
The limit as x approaches 0+of (sin(x^2))/x is 0