What is (\partial)/(\partial y)(-y/(x^2)) ?

The answer to (\partial)/(\partial y)(-y/(x^2)) is -1/(x^2)

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(\partial)/(\partial y)(-y/(x^2))

\frac{\partial}{\partial y} (- \frac{y}{x ^{2}})

- \frac{1}{x ^{2}}

Solution steps

\frac{\partial}{\partial y} (- \frac{y}{x ^{2}})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{x ^{2}} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= - \frac{1}{x ^{2}} \cdot 1

Simplify

= - \frac{1}{x ^{2}}

\int 4 x^{7} d x

f (x) = 0.0622 x^{2} + 1.1119 x + 2.3979

y = x^{5}

\int \frac{10}{x} d x

R (q) = (q^{2} + 1)^{4}

What is (\partial)/(\partial y)(-y/(x^2)) ?
The answer to (\partial)/(\partial y)(-y/(x^2)) is -1/(x^2)