What is the solution for y^'+(1-2x)/(x^2)y-1=0 ?

The solution for y^'+(1-2x)/(x^2)y-1=0 is y=x^2+(c_{1}x^2}{e^{\frac{-1+2x+c_{1}x)/x}}

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y^'+(1-2x)/(x^2)y-1=0

y^{^{'}} + \frac{1 - 2 x}{x ^{2}} y - 1 = 0

y = x^{2} + \frac{c _{1} x ^{2}}{e ^{\frac{- 1 + 2 x + c _{1} x}{x}}}

Solution steps

y^{'} (x) + \frac{1 - 2 x}{x ^{2}} y - 1 = 0

Solve linear ODE:

y = x^{2} + \frac{c _{1} x ^{2}}{e ^{\frac{- 1 + 2 x + c _{1} x}{x}}}

y = x^{2} + \frac{c _{1} x ^{2}}{e ^{\frac{- 1 + 2 x + c _{1} x}{x}}}

\frac{\partial}{\partial y} (x y + yz + zy)

f (x) = - \frac{1}{9} (x^{- 9} - x^{18})

\int \frac{1}{16 e ^{- 5 x} + e ^{5 x}} d x

(4 - x) y^{2} = x^{3}, (2, 2)

\frac{\partial}{\partial y} (- \frac{y}{x ^{2}})

What is the solution for y^'+(1-2x)/(x^2)y-1=0 ?
The solution for y^'+(1-2x)/(x^2)y-1=0 is y=x^2+(c_{1}x^2}{e^{\frac{-1+2x+c_{1}x)/x}}