What is the answer to 2^x=7 ?

The answer to 2^x=7 is x=(ln(7))/(ln(2))

The solution is x=(ln(7))/(ln(2))

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2^x=7

2^{x} = 7

x = \frac{ln ( 7 )}{ln ( 2 )}

Decimal Notation

x = 2.80735 \dots

Solution steps

2^{x} = 7

Apply exponent rules

x ln (2) = ln (7)

Solve

x ln (2) = ln (7) : x = \frac{ln ( 7 )}{ln ( 2 )}

x = \frac{ln ( 7 )}{ln ( 2 )}

\frac{3 3}{3}

7 x + 3 \geq (x^{2} + 2)

\frac{1}{3} + \frac{2}{3} - \frac{7}{3}

\frac{( \frac{3 x + y}{2 x y} )}{( \frac{5 x}{x + 2} )}

∣ 10 x + 2 ∣ > 5