What are the solutions to the equation 2x^2+8=12x ?

The solutions to the equation 2x^2+8=12x are x=3+sqrt(5),x=3-sqrt(5)

Find the zeros of 2x^2+8=12x

The zeros of 2x^2+8=12x are x=3+sqrt(5),x=3-sqrt(5)

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2 x^{2} + 8 = 12 x

x = 3 + 5, x = 3 - 5

Decimal Notation

x = 5.23606 \dots, x = 0.76393 \dots

Solution steps

2 x^{2} + 8 = 12 x

Move

12 x

to the left side

2 x^{2} + 8 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 12 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 8 = 45

x_{1, 2} = \frac{- ( - 12 ) \pm 4 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 5}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 4 5}{2 \cdot 2}

x = \frac{- ( - 12 ) + 4 5}{2 \cdot 2} : 3 + 5

x = \frac{- ( - 12 ) - 4 5}{2 \cdot 2} : 3 - 5

The solutions to the quadratic equation are:

x = 3 + 5, x = 3 - 5

4 x^{2} + 10 = 0

x^{3} + 729

\frac{- 20}{- 4}

x^{2} + 3 x - 20 = 0

- 5 x + 2 x = 13

What are the solutions to the equation 2x^2+8=12x ?
The solutions to the equation 2x^2+8=12x are x=3+sqrt(5),x=3-sqrt(5)
Find the zeros of 2x^2+8=12x
The zeros of 2x^2+8=12x are x=3+sqrt(5),x=3-sqrt(5)