What are the solutions to the equation x^2+3x-20=0 ?

The solutions to the equation x^2+3x-20=0 are x=(-3+sqrt(89))/2 ,x=(-3-sqrt(89))/2

Find the zeros of x^2+3x-20=0

The zeros of x^2+3x-20=0 are x=(-3+sqrt(89))/2 ,x=(-3-sqrt(89))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 3 x - 20 = 0

x = \frac{- 3 + 89}{2}, x = \frac{- 3 - 89}{2}

Decimal Notation

x = 3.21699 \dots, x = - 6.21699 \dots

Solution steps

x^{2} + 3 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 20) = 89

x_{1, 2} = \frac{- 3 \pm 89}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 89}{2 \cdot 1}, x_{2} = \frac{- 3 - 89}{2 \cdot 1}

x = \frac{- 3 + 89}{2 \cdot 1} : \frac{- 3 + 89}{2}

x = \frac{- 3 - 89}{2 \cdot 1} : \frac{- 3 - 89}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 89}{2}, x = \frac{- 3 - 89}{2}

- 5 x + 2 x = 13

4 x^{2} + 55 = - 28 x

- \frac{5}{2} + 6

e^{- y} + e^{- 2 x - y}

6 x^{2} + 8 x - 8 \leq 0

What are the solutions to the equation x^2+3x-20=0 ?
The solutions to the equation x^2+3x-20=0 are x=(-3+sqrt(89))/2 ,x=(-3-sqrt(89))/2
Find the zeros of x^2+3x-20=0
The zeros of x^2+3x-20=0 are x=(-3+sqrt(89))/2 ,x=(-3-sqrt(89))/2