What are the solutions to the equation 3(x-4)(x-5)=0 ?

The solutions to the equation 3(x-4)(x-5)=0 are x=4,x=5

Find the zeros of 3(x-4)(x-5)=0

The zeros of 3(x-4)(x-5)=0 are x=4,x=5

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3 (x - 4) (x - 5) = 0

x = 4, x = 5

Solution steps

3 (x - 4) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x - 5 = 0

Solve

x - 4 = 0 : x = 4

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = 4, x = 5

x^{3} (6 x^{2} + x) \geq 2 x^{3}

12 (5 + 2 y) = 4 y - (5 - 9 y)

5^{\frac{1}{2}} \cdot 5^{\frac{1}{2}}

x m + y m + x n + y n

- 9 \cdot - 36

What are the solutions to the equation 3(x-4)(x-5)=0 ?
The solutions to the equation 3(x-4)(x-5)=0 are x=4,x=5
Find the zeros of 3(x-4)(x-5)=0
The zeros of 3(x-4)(x-5)=0 are x=4,x=5