x^2+2x+4=3

解

x^{2} + 2 x + 4 = 3

x = - 1

解答ステップ

x^{2} + 2 x + 4 = 3

3

を左側に移動します

x^{2} + 2 x + 1 = 0

解くとthe二次式

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

二次equationの解:

x = - 1