What are the solutions to the equation 4x^2+31x=3x ?

The solutions to the equation 4x^2+31x=3x are x=0,x=-7

Find the zeros of 4x^2+31x=3x

The zeros of 4x^2+31x=3x are x=0,x=-7

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4 x^{2} + 31 x = 3 x

x = 0, x = - 7

Solution steps

4 x^{2} + 31 x = 3 x

Move

3 x

to the left side

4 x^{2} + 28 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

2 8^{2} - 4 \cdot 4 \cdot 0 = 28

x_{1, 2} = \frac{- 28 \pm 28}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 28 + 28}{2 \cdot 4}, x_{2} = \frac{- 28 - 28}{2 \cdot 4}

x = \frac{- 28 + 28}{2 \cdot 4} : 0

x = \frac{- 28 - 28}{2 \cdot 4} : - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

x^{2} + b x

\frac{k}{k}

2 n^{2} - 11 n + 5

\frac{- 5 + 3 i}{1 - 4 i}

x^{2} - 49 = 0

What are the solutions to the equation 4x^2+31x=3x ?
The solutions to the equation 4x^2+31x=3x are x=0,x=-7
Find the zeros of 4x^2+31x=3x
The zeros of 4x^2+31x=3x are x=0,x=-7