What are the solutions to the equation 2x^2+20x=10 ?

The solutions to the equation 2x^2+20x=10 are x=-5+sqrt(30),x=-5-sqrt(30)

Find the zeros of 2x^2+20x=10

The zeros of 2x^2+20x=10 are x=-5+sqrt(30),x=-5-sqrt(30)

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2 x^{2} + 20 x = 10

x = - 5 + 30, x = - 5 - 30

Decimal Notation

x = 0.47722 \dots, x = - 10.47722 \dots

Solution steps

2 x^{2} + 20 x = 10

Move

10

to the left side

2 x^{2} + 20 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 (- 10) = 430

x_{1, 2} = \frac{- 20 \pm 4 30}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 4 30}{2 \cdot 2}, x_{2} = \frac{- 20 - 4 30}{2 \cdot 2}

x = \frac{- 20 + 4 30}{2 \cdot 2} : - 5 + 30

x = \frac{- 20 - 4 30}{2 \cdot 2} : - 5 - 30

The solutions to the quadratic equation are:

x = - 5 + 30, x = - 5 - 30

\frac{3}{2 + 5}

\frac{( 5 x - 4 ) \cdot ( 5 x + 4 )}{4} = \frac{( 3 x - 1 ) ^{2} - 9}{2}

12 y^{2} + 23 y + 5 = 0

- \frac{3}{2} x^{- \frac{3}{2}}

12 m^{3} - 14 m^{2} - 30 m + 35

What are the solutions to the equation 2x^2+20x=10 ?
The solutions to the equation 2x^2+20x=10 are x=-5+sqrt(30),x=-5-sqrt(30)
Find the zeros of 2x^2+20x=10
The zeros of 2x^2+20x=10 are x=-5+sqrt(30),x=-5-sqrt(30)