What are the solutions to the equation -x^2+1.8x+2.5=0 ?

The solutions to the equation -x^2+1.8x+2.5=0 are x=-(-9+sqrt(331))/(10),x=(9+sqrt(331))/(10)

Find the zeros of -x^2+1.8x+2.5=0

The zeros of -x^2+1.8x+2.5=0 are x=-(-9+sqrt(331))/(10),x=(9+sqrt(331))/(10)

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- x^{2} + 1.8 x + 2.5 = 0

x = - \frac{- 9 + 331}{10}, x = \frac{9 + 331}{10}

Decimal Notation

x = - 0.91934 \dots, x = 2.71934 \dots

Solution steps

- x^{2} + 1.8 x + 2.5 = 0

Multiply both sides by

10

- 10 x^{2} + 18 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 10 ) \cdot 25}{2 ( - 10 )}

1 8^{2} - 4 (- 10) \cdot 25 = 2331

x_{1, 2} = \frac{- 18 \pm 2 331}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- 18 + 2 331}{2 ( - 10 )}, x_{2} = \frac{- 18 - 2 331}{2 ( - 10 )}

x = \frac{- 18 + 2 331}{2 ( - 10 )} : - \frac{- 9 + 331}{10}

x = \frac{- 18 - 2 331}{2 ( - 10 )} : \frac{9 + 331}{10}

The solutions to the quadratic equation are:

x = - \frac{- 9 + 331}{10}, x = \frac{9 + 331}{10}

38 x = 14 x - 42

5 x^{2} - 4 x = 9

8 x - 7 = 4 + 7 x

(\frac{- 3}{4})^{- 3}

\frac{9 !}{6 ! ( 9 - 6 ) !}

What are the solutions to the equation -x^2+1.8x+2.5=0 ?
The solutions to the equation -x^2+1.8x+2.5=0 are x=-(-9+sqrt(331))/(10),x=(9+sqrt(331))/(10)
Find the zeros of -x^2+1.8x+2.5=0
The zeros of -x^2+1.8x+2.5=0 are x=-(-9+sqrt(331))/(10),x=(9+sqrt(331))/(10)