What are the solutions to the equation 5x^2-4x=9 ?

The solutions to the equation 5x^2-4x=9 are x= 9/5 ,x=-1

Find the zeros of 5x^2-4x=9

The zeros of 5x^2-4x=9 are x= 9/5 ,x=-1

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5 x^{2} - 4 x = 9

x = \frac{9}{5}, x = - 1

Decimal Notation

x = 1.8, x = - 1

Solution steps

5 x^{2} - 4 x = 9

Move

9

to the left side

5 x^{2} - 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 9) = 14

x_{1, 2} = \frac{- ( - 4 ) \pm 14}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 14}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 14}{2 \cdot 5}

x = \frac{- ( - 4 ) + 14}{2 \cdot 5} : \frac{9}{5}

x = \frac{- ( - 4 ) - 14}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

x = \frac{9}{5}, x = - 1

8 x - 7 = 4 + 7 x

(\frac{- 3}{4})^{- 3}

\frac{9 !}{6 ! ( 9 - 6 ) !}

5 x^{3} - 40

What are the solutions to the equation 5x^2-4x=9 ?
The solutions to the equation 5x^2-4x=9 are x= 9/5 ,x=-1
Find the zeros of 5x^2-4x=9
The zeros of 5x^2-4x=9 are x= 9/5 ,x=-1