What is |x+2|+|x-2|>= 10 ?

The solution to |x+2|+|x-2|>= 10 is x = 5

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|x+2|+|x-2|>= 10

∣ x + 2 ∣ + ∣ x - 2 ∣ \geq 10

x \leq - 5 or x \geq 5

Interval Notation

(- \infty, - 5] \cup [5, \infty)

Solution steps

∣ x + 2 ∣ + ∣ x - 2 ∣ \geq 10

Find positive and negative intervals

x < - 2, - 2 \leq x < 2, x \geq 2

Solve the inequality for each interval

x \leq - 5 or No Solution or x \geq 5

Merge Overlapping Intervals

x \leq - 5 or x \geq 5

15 x^{2} + x - 14 = 0

4 p \leq - 4

11.85 X = 0

w - 5 \leq 2 w

(x + i) (x - i)