What are the solutions to the equation 15x^2+x-14=0 ?

The solutions to the equation 15x^2+x-14=0 are x= 14/15 ,x=-1

Find the zeros of 15x^2+x-14=0

The zeros of 15x^2+x-14=0 are x= 14/15 ,x=-1

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15 x^{2} + x - 14 = 0

x = \frac{14}{15}, x = - 1

Decimal Notation

x = 0.93333 \dots, x = - 1

Solution steps

15 x^{2} + x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 15 ( - 14 )}{2 \cdot 15}

1^{2} - 4 \cdot 15 (- 14) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 15}, x_{2} = \frac{- 1 - 29}{2 \cdot 15}

x = \frac{- 1 + 29}{2 \cdot 15} : \frac{14}{15}

x = \frac{- 1 - 29}{2 \cdot 15} : - 1

The solutions to the quadratic equation are:

x = \frac{14}{15}, x = - 1

4 p \leq - 4

11.85 X = 0

w - 5 \leq 2 w

(x + i) (x - i)

What are the solutions to the equation 15x^2+x-14=0 ?
The solutions to the equation 15x^2+x-14=0 are x= 14/15 ,x=-1
Find the zeros of 15x^2+x-14=0
The zeros of 15x^2+x-14=0 are x= 14/15 ,x=-1