What are the solutions to the equation (y-9)(y+8)=0 ?

The solutions to the equation (y-9)(y+8)=0 are y=9,y=-8

Find the zeros of (y-9)(y+8)=0

The zeros of (y-9)(y+8)=0 are y=9,y=-8

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(y - 9) (y + 8) = 0

y = 9, y = - 8

Solution steps

(y - 9) (y + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - 9 = 0 or y + 8 = 0

Solve

y - 9 = 0 : y = 9

Solve

y + 8 = 0 : y = - 8

The solutions to the quadratic equation are:

y = 9, y = - 8

\frac{2}{3} (x + 7) = 6

\frac{- 12 + - 18}{60}

lo g_{2} (\frac{1}{4})

49

2 4^{2} + b^{2} = 2 5^{2}

What are the solutions to the equation (y-9)(y+8)=0 ?
The solutions to the equation (y-9)(y+8)=0 are y=9,y=-8
Find the zeros of (y-9)(y+8)=0
The zeros of (y-9)(y+8)=0 are y=9,y=-8