What are the solutions to the equation 24^2+b^2=25^2 ?

The solutions to the equation 24^2+b^2=25^2 are b=7,b=-7

Find the zeros of 24^2+b^2=25^2

The zeros of 24^2+b^2=25^2 are b=7,b=-7

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2 4^{2} + b^{2} = 2 5^{2}

b = 7, b = - 7

Solution steps

2 4^{2} + b^{2} = 2 5^{2}

Move

2 4^{2}

to the right side

b^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 49, b = - 49

49 = 7

- 49 = - 7

b = 7, b = - 7

(x - 3) (x + 5) (2 x + 5) < 0

x - 20 = 5 (7 x - 4)

(2 y^{4})^{3}

15 x^{2} - 10 x - 40

x - 3 \leq 4

What are the solutions to the equation 24^2+b^2=25^2 ?
The solutions to the equation 24^2+b^2=25^2 are b=7,b=-7
Find the zeros of 24^2+b^2=25^2
The zeros of 24^2+b^2=25^2 are b=7,b=-7