What are the solutions to the equation 4g^2+10=11 ?

The solutions to the equation 4g^2+10=11 are g= 1/2 ,g=-1/2

Find the zeros of 4g^2+10=11

The zeros of 4g^2+10=11 are g= 1/2 ,g=-1/2

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4 g^{2} + 10 = 11

g = \frac{1}{2}, g = - \frac{1}{2}

Decimal Notation

g = 0.5, g = - 0.5

Solution steps

4 g^{2} + 10 = 11

Move

10

to the right side

4 g^{2} = 1

Divide both sides by

4

g^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

g = \frac{1}{4}, g = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

g = \frac{1}{2}, g = - \frac{1}{2}

\frac{3}{1 - x} \geq \frac{4}{x + 3}

m^{2} + 22 m - 23

- 2 (- 9 b + 7) + 30 = 5 b + 29

6 ab - 8 ab

- 2 x - 7 + 3 x = 10

What are the solutions to the equation 4g^2+10=11 ?
The solutions to the equation 4g^2+10=11 are g= 1/2 ,g=-1/2
Find the zeros of 4g^2+10=11
The zeros of 4g^2+10=11 are g= 1/2 ,g=-1/2