What is 3/(1-x)>= 4/(x+3) ?

The solution to 3/(1-x)>= 4/(x+3) is x<-3\lor-5/7 <= x<1

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3/(1-x)>= 4/(x+3)

\frac{3}{1 - x} \geq \frac{4}{x + 3}

x < - 3 or - \frac{5}{7} \leq x < 1

Interval Notation

(- \infty, - 3) \cup [- \frac{5}{7}, 1)

Decimal Notation

x < - 3 or - 0.71428 \dots \leq x < 1

Solution steps

\frac{3}{1 - x} \geq \frac{4}{x + 3}

Rewrite in standard form

\frac{7 x + 5}{( - x + 1 ) ( x + 3 )} \geq 0

Identify the intervals

x < - 3 or - \frac{5}{7} \leq x < 1

m^{2} + 22 m - 23

- 2 (- 9 b + 7) + 30 = 5 b + 29

6 ab - 8 ab

- 2 x - 7 + 3 x = 10

\frac{9}{2} \cdot (- \frac{1}{9})

What is 3/(1-x)>= 4/(x+3) ?
The solution to 3/(1-x)>= 4/(x+3) is x<-3\lor-5/7 <= x<1