What is the answer to -2(y-4)=20-2y-12 ?

The answer to -2(y-4)=20-2y-12 is True for all y

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-2(y-4)=20-2y-12

- 2 (y - 4) = 20 - 2 y - 12

True for all y

Solution steps

- 2 (y - 4) = 20 - 2 y - 12

Group like terms

- 2 (y - 4) = - 2 y + 20 - 12

Add/Subtract the numbers:

20 - 12 = 8

- 2 (y - 4) = - 2 y + 8

Expand

- 2 (y - 4) : - 2 y + 8

- 2 y + 8 = - 2 y + 8

Move

8

to the right side

- 2 y = - 2 y

Move

2 y

to the left side

0 = 0

Both sides are equal

True for all y

- 6 x + 35 = - 6 x - 35

(x - 3) (x - 5) = 0

5 a^{2} b - 10 a^{2} b^{2}

(\frac{x ^{2}}{- 3 y ^{4}})^{4}

2 x \leq 3 x + 2 < x + 6

What is the answer to -2(y-4)=20-2y-12 ?
The answer to -2(y-4)=20-2y-12 is True for all y
Solve for y: -2(y-4)=20-2y-12
The solution is True for all y