What are the solutions to the equation (x-3)(x-5)=0 ?

The solutions to the equation (x-3)(x-5)=0 are x=3,x=5

Find the zeros of (x-3)(x-5)=0

The zeros of (x-3)(x-5)=0 are x=3,x=5

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(x - 3) (x - 5) = 0

x = 3, x = 5

Solution steps

(x - 3) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x - 5 = 0

Solve

x - 3 = 0 : x = 3

Solve

x - 5 = 0 : x = 5

The solutions to the quadratic equation are:

x = 3, x = 5

5 a^{2} b - 10 a^{2} b^{2}

(\frac{x ^{2}}{- 3 y ^{4}})^{4}

2 x \leq 3 x + 2 < x + 6

(9 + i) (9 - i)

2^{2 x + 1} - 1 > - 0.75

What are the solutions to the equation (x-3)(x-5)=0 ?
The solutions to the equation (x-3)(x-5)=0 are x=3,x=5
Find the zeros of (x-3)(x-5)=0
The zeros of (x-3)(x-5)=0 are x=3,x=5