What are the solutions to the equation 2x^2-20=0 ?

The solutions to the equation 2x^2-20=0 are x=sqrt(10),x=-sqrt(10)

Find the zeros of 2x^2-20=0

The zeros of 2x^2-20=0 are x=sqrt(10),x=-sqrt(10)

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2 x^{2} - 20 = 0

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

2 x^{2} - 20 = 0

Move

20

to the right side

2 x^{2} = 20

Divide both sides by

2

x^{2} = 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

x^{3} + 4 x^{2} \geq 4 x + 16

3 x - \frac{1}{2} = 1 \frac{1}{2}

4 x^{2} - 80 x = - 372

4 x^{2} - 25 x + 25

\frac{18 !}{( 18 - 3 ) !}

What are the solutions to the equation 2x^2-20=0 ?
The solutions to the equation 2x^2-20=0 are x=sqrt(10),x=-sqrt(10)
Find the zeros of 2x^2-20=0
The zeros of 2x^2-20=0 are x=sqrt(10),x=-sqrt(10)