What are the solutions to the equation 4x^2-80x=-372 ?

The solutions to the equation 4x^2-80x=-372 are x=10+sqrt(7),x=10-sqrt(7)

Find the zeros of 4x^2-80x=-372

The zeros of 4x^2-80x=-372 are x=10+sqrt(7),x=10-sqrt(7)

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4 x^{2} - 80 x = - 372

x = 10 + 7, x = 10 - 7

Decimal Notation

x = 12.64575 \dots, x = 7.35424 \dots

Solution steps

4 x^{2} - 80 x = - 372

Move

372

to the left side

4 x^{2} - 80 x + 372 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 4 \cdot 372}{2 \cdot 4}

(- 80)^{2} - 4 \cdot 4 \cdot 372 = 87

x_{1, 2} = \frac{- ( - 80 ) \pm 8 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 80 ) + 8 7}{2 \cdot 4}, x_{2} = \frac{- ( - 80 ) - 8 7}{2 \cdot 4}

x = \frac{- ( - 80 ) + 8 7}{2 \cdot 4} : 10 + 7

x = \frac{- ( - 80 ) - 8 7}{2 \cdot 4} : 10 - 7

The solutions to the quadratic equation are:

x = 10 + 7, x = 10 - 7

4 x^{2} - 25 x + 25

\frac{18 !}{( 18 - 3 ) !}

- 72

ab - 2 b - a + 2

13 x - 3 = 4 (3 x + 4) - 13

What are the solutions to the equation 4x^2-80x=-372 ?
The solutions to the equation 4x^2-80x=-372 are x=10+sqrt(7),x=10-sqrt(7)
Find the zeros of 4x^2-80x=-372
The zeros of 4x^2-80x=-372 are x=10+sqrt(7),x=10-sqrt(7)