What are the solutions to the equation 4x^2+4x-1=0 ?

The solutions to the equation 4x^2+4x-1=0 are x=(-1+sqrt(2))/2 ,x=-(1+sqrt(2))/2

Find the zeros of 4x^2+4x-1=0

The zeros of 4x^2+4x-1=0 are x=(-1+sqrt(2))/2 ,x=-(1+sqrt(2))/2

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4 x^{2} + 4 x - 1 = 0

x = \frac{- 1 + 2}{2}, x = - \frac{1 + 2}{2}

Decimal Notation

x = 0.20710 \dots, x = - 1.20710 \dots

Solution steps

4 x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 1) = 42

x_{1, 2} = \frac{- 4 \pm 4 2}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 4 + 4 2}{2 \cdot 4}, x_{2} = \frac{- 4 - 4 2}{2 \cdot 4}

x = \frac{- 4 + 4 2}{2 \cdot 4} : \frac{- 1 + 2}{2}

x = \frac{- 4 - 4 2}{2 \cdot 4} : - \frac{1 + 2}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2}{2}, x = - \frac{1 + 2}{2}

9 x^{2} + 6 x + 3

e^{0.06}

x^{2} + 5 x + 14 = 0

6 x^{3} (2 - y) - 8 x^{2} (2 - y) + 4 x (y - 2)

5 x + 9 \geq - 1

What are the solutions to the equation 4x^2+4x-1=0 ?
The solutions to the equation 4x^2+4x-1=0 are x=(-1+sqrt(2))/2 ,x=-(1+sqrt(2))/2
Find the zeros of 4x^2+4x-1=0
The zeros of 4x^2+4x-1=0 are x=(-1+sqrt(2))/2 ,x=-(1+sqrt(2))/2