What are the solutions to the equation x^2+5x+14=0 ?

The solutions to the equation x^2+5x+14=0 are x=-5/2+i(sqrt(31))/2 ,x=-5/2-i(sqrt(31))/2

Find the zeros of x^2+5x+14=0

The zeros of x^2+5x+14=0 are x=-5/2+i(sqrt(31))/2 ,x=-5/2-i(sqrt(31))/2

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x^{2} + 5 x + 14 = 0

x = - \frac{5}{2} + i \frac{31}{2}, x = - \frac{5}{2} - i \frac{31}{2}

Solution steps

x^{2} + 5 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 14 : 31 i

x_{1, 2} = \frac{- 5 \pm 31 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 31 i}{2 \cdot 1}, x_{2} = \frac{- 5 - 31 i}{2 \cdot 1}

x = \frac{- 5 + 31 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{31}{2}

x = \frac{- 5 - 31 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{31}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{31}{2}, x = - \frac{5}{2} - i \frac{31}{2}

6 x^{3} (2 - y) - 8 x^{2} (2 - y) + 4 x (y - 2)

5 x + 9 \geq - 1

x^{2} \leq 13

10 x^{2} - 31 x + 15

(\frac{9 x ^{3} y}{y ^{- 3}})^{\frac{1}{2}}

What are the solutions to the equation x^2+5x+14=0 ?
The solutions to the equation x^2+5x+14=0 are x=-5/2+i(sqrt(31))/2 ,x=-5/2-i(sqrt(31))/2
Find the zeros of x^2+5x+14=0
The zeros of x^2+5x+14=0 are x=-5/2+i(sqrt(31))/2 ,x=-5/2-i(sqrt(31))/2