What are the solutions to the equation -1=2x^2-x-1 ?

The solutions to the equation -1=2x^2-x-1 are x= 1/2 ,x=0

Find the zeros of -1=2x^2-x-1

The zeros of -1=2x^2-x-1 are x= 1/2 ,x=0

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- 1 = 2 x^{2} - x - 1

x = \frac{1}{2}, x = 0

Decimal Notation

x = 0.5, x = 0

Solution steps

- 1 = 2 x^{2} - x - 1

Switch sides

2 x^{2} - x - 1 = - 1

Move

1

to the left side

2 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 2}

x = \frac{- ( - 1 ) + 1}{2 \cdot 2} : \frac{1}{2}

x = \frac{- ( - 1 ) - 1}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = 0

4 x^{2} - 8 x - 8 = 1

27 - z = - 12

\frac{300 π}{180}

7 x - 4 = 6 x + 2

- 0.1 x^{2} + 90 x - 20000 = 0

What are the solutions to the equation -1=2x^2-x-1 ?
The solutions to the equation -1=2x^2-x-1 are x= 1/2 ,x=0
Find the zeros of -1=2x^2-x-1
The zeros of -1=2x^2-x-1 are x= 1/2 ,x=0