What are the solutions to the equation 4x^2-8x-8=1 ?

The solutions to the equation 4x^2-8x-8=1 are x=(2+sqrt(13))/2 ,x=(2-sqrt(13))/2

Find the zeros of 4x^2-8x-8=1

The zeros of 4x^2-8x-8=1 are x=(2+sqrt(13))/2 ,x=(2-sqrt(13))/2

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4 x^{2} - 8 x - 8 = 1

x = \frac{2 + 13}{2}, x = \frac{2 - 13}{2}

Decimal Notation

x = 2.80277 \dots, x = - 0.80277 \dots

Solution steps

4 x^{2} - 8 x - 8 = 1

Move

1

to the left side

4 x^{2} - 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 9) = 413

x_{1, 2} = \frac{- ( - 8 ) \pm 4 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 13}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 13}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 13}{2 \cdot 4} : \frac{2 + 13}{2}

x = \frac{- ( - 8 ) - 4 13}{2 \cdot 4} : \frac{2 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{2 + 13}{2}, x = \frac{2 - 13}{2}

27 - z = - 12

\frac{300 π}{180}

7 x - 4 = 6 x + 2

- 0.1 x^{2} + 90 x - 20000 = 0

\frac{( \frac{3}{2} ) ^{- 2}}{( \frac{2}{3} ) ^{- 3}}

What are the solutions to the equation 4x^2-8x-8=1 ?
The solutions to the equation 4x^2-8x-8=1 are x=(2+sqrt(13))/2 ,x=(2-sqrt(13))/2
Find the zeros of 4x^2-8x-8=1
The zeros of 4x^2-8x-8=1 are x=(2+sqrt(13))/2 ,x=(2-sqrt(13))/2