What are the solutions to the equation 2x(x+4)=-3.5 ?

The solutions to the equation 2x(x+4)=-3.5 are x=-1/2 ,x=-7/2

Find the zeros of 2x(x+4)=-3.5

The zeros of 2x(x+4)=-3.5 are x=-1/2 ,x=-7/2

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2 x (x + 4) = - 3.5

x = - \frac{1}{2}, x = - \frac{7}{2}

Decimal Notation

x = - 0.5, x = - 3.5

Solution steps

2 x (x + 4) = - 3.5

Multiply both sides by

10

20 x (x + 4) = - 35

Expand

20 x (x + 4) : 20 x^{2} + 80 x

20 x^{2} + 80 x = - 35

Move

35

to the left side

20 x^{2} + 80 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 20 \cdot 35}{2 \cdot 20}

8 0^{2} - 4 \cdot 20 \cdot 35 = 60

x_{1, 2} = \frac{- 80 \pm 60}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 80 + 60}{2 \cdot 20}, x_{2} = \frac{- 80 - 60}{2 \cdot 20}

x = \frac{- 80 + 60}{2 \cdot 20} : - \frac{1}{2}

x = \frac{- 80 - 60}{2 \cdot 20} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{7}{2}

3 x^{2} + 4 x + 1

6 + 8 i

x (x^{\frac{1}{4}})

∣ x + 7 ∣ \leq 6

\frac{x ^{x} + x ^{x - n} y ^{x}}{x ^{n} + y ^{x}}

What are the solutions to the equation 2x(x+4)=-3.5 ?
The solutions to the equation 2x(x+4)=-3.5 are x=-1/2 ,x=-7/2
Find the zeros of 2x(x+4)=-3.5
The zeros of 2x(x+4)=-3.5 are x=-1/2 ,x=-7/2