What is factor 3x^2+4x+1 ?

The solution to factor 3x^2+4x+1 is (3x+1)(x+1)

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factor 3x^2+4x+1

factor

3 x^{2} + 4 x + 1

(3 x + 1) (x + 1)

Solution steps

3 x^{2} + 4 x + 1

Break the expression into groups

= (3 x^{2} + x) + (3 x + 1)

Factor out

x

from

3 x^{2} + x : x (3 x + 1)

= x (3 x + 1) + (3 x + 1)

Factor out common term

(3 x + 1) : (3 x + 1) (x + 1)

= (3 x + 1) (x + 1)

6 + 8 i

x (x^{\frac{1}{4}})

∣ x + 7 ∣ \leq 6

\frac{x ^{x} + x ^{x - n} y ^{x}}{x ^{n} + y ^{x}}

2 x + 3 (x - 3) = 6 [2 x - 3 (x - 5)]