What are the solutions to the equation 6x-3x^2=2 ?

The solutions to the equation 6x-3x^2=2 are x=(3-sqrt(3))/3 ,x=(3+sqrt(3))/3

Find the zeros of 6x-3x^2=2

The zeros of 6x-3x^2=2 are x=(3-sqrt(3))/3 ,x=(3+sqrt(3))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x - 3 x^{2} = 2

x = \frac{3 - 3}{3}, x = \frac{3 + 3}{3}

Decimal Notation

x = 0.42264 \dots, x = 1.57735 \dots

Solution steps

6 x - 3 x^{2} = 2

Move

2

to the left side

6 x - 3 x^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 2 )}{2 ( - 3 )}

6^{2} - 4 (- 3) (- 2) = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 ( - 3 )}, x_{2} = \frac{- 6 - 2 3}{2 ( - 3 )}

x = \frac{- 6 + 2 3}{2 ( - 3 )} : \frac{3 - 3}{3}

x = \frac{- 6 - 2 3}{2 ( - 3 )} : \frac{3 + 3}{3}

The solutions to the quadratic equation are:

x = \frac{3 - 3}{3}, x = \frac{3 + 3}{3}

- 40 + 16 \leq 3 m + 6

x^{2} + 5 x - 1 = 0

- 4 + \frac{x}{2} = 7

9 x^{2} + x + 1 = 0

What are the solutions to the equation 6x-3x^2=2 ?
The solutions to the equation 6x-3x^2=2 are x=(3-sqrt(3))/3 ,x=(3+sqrt(3))/3
Find the zeros of 6x-3x^2=2
The zeros of 6x-3x^2=2 are x=(3-sqrt(3))/3 ,x=(3+sqrt(3))/3