What are the solutions to the equation x^2+5x-1=0 ?

The solutions to the equation x^2+5x-1=0 are x=(-5+sqrt(29))/2 ,x=(-5-sqrt(29))/2

Find the zeros of x^2+5x-1=0

The zeros of x^2+5x-1=0 are x=(-5+sqrt(29))/2 ,x=(-5-sqrt(29))/2

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x^{2} + 5 x - 1 = 0

x = \frac{- 5 + 29}{2}, x = \frac{- 5 - 29}{2}

Decimal Notation

x = 0.19258 \dots, x = - 5.19258 \dots

Solution steps

x^{2} + 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 1) = 29

x_{1, 2} = \frac{- 5 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 29}{2 \cdot 1}, x_{2} = \frac{- 5 - 29}{2 \cdot 1}

x = \frac{- 5 + 29}{2 \cdot 1} : \frac{- 5 + 29}{2}

x = \frac{- 5 - 29}{2 \cdot 1} : \frac{- 5 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 29}{2}, x = \frac{- 5 - 29}{2}

- 4 + \frac{x}{2} = 7

9 x^{2} + x + 1 = 0

x - \frac{x - y}{x + y}

\frac{14}{3}

What are the solutions to the equation x^2+5x-1=0 ?
The solutions to the equation x^2+5x-1=0 are x=(-5+sqrt(29))/2 ,x=(-5-sqrt(29))/2
Find the zeros of x^2+5x-1=0
The zeros of x^2+5x-1=0 are x=(-5+sqrt(29))/2 ,x=(-5-sqrt(29))/2