What are the solutions to the equation x^2+2x=-4 ?

The solutions to the equation x^2+2x=-4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of x^2+2x=-4

The zeros of x^2+2x=-4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

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x^{2} + 2 x = - 4

x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

x^{2} + 2 x = - 4

Move

4

to the left side

x^{2} + 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

x = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

x = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

x = - 1 + 3 i, x = - 1 - 3 i

\frac{3}{4} + \frac{6}{5}

\frac{2 x - 1}{x} > 0

9 x^{2} + 3 x - 4 = 0

4.6 + 1.2 x = 54.6 - 0.8 x

(u^{2} + 5 u^{2} v + 4 u v^{2}) - (u^{2} + 5 u^{2} v^{2} + 4 uv)

What are the solutions to the equation x^2+2x=-4 ?
The solutions to the equation x^2+2x=-4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of x^2+2x=-4
The zeros of x^2+2x=-4 are x=-1+sqrt(3)i,x=-1-sqrt(3)i