What are the solutions to the equation 9x^2+3x-4=0 ?

The solutions to the equation 9x^2+3x-4=0 are x=(-1+sqrt(17))/6 ,x=-(1+sqrt(17))/6

Find the zeros of 9x^2+3x-4=0

The zeros of 9x^2+3x-4=0 are x=(-1+sqrt(17))/6 ,x=-(1+sqrt(17))/6

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9 x^{2} + 3 x - 4 = 0

x = \frac{- 1 + 17}{6}, x = - \frac{1 + 17}{6}

Decimal Notation

x = 0.52051 \dots, x = - 0.85385 \dots

Solution steps

9 x^{2} + 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 9 ( - 4 )}{2 \cdot 9}

3^{2} - 4 \cdot 9 (- 4) = 317

x_{1, 2} = \frac{- 3 \pm 3 17}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 3 + 3 17}{2 \cdot 9}, x_{2} = \frac{- 3 - 3 17}{2 \cdot 9}

x = \frac{- 3 + 3 17}{2 \cdot 9} : \frac{- 1 + 17}{6}

x = \frac{- 3 - 3 17}{2 \cdot 9} : - \frac{1 + 17}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 17}{6}, x = - \frac{1 + 17}{6}

4.6 + 1.2 x = 54.6 - 0.8 x

(u^{2} + 5 u^{2} v + 4 u v^{2}) - (u^{2} + 5 u^{2} v^{2} + 4 uv)

y - (- 10) = - 41

x^{2} - 12 x + 61 = 0

2 0^{2} + 2 1^{2} = c^{2}

What are the solutions to the equation 9x^2+3x-4=0 ?
The solutions to the equation 9x^2+3x-4=0 are x=(-1+sqrt(17))/6 ,x=-(1+sqrt(17))/6
Find the zeros of 9x^2+3x-4=0
The zeros of 9x^2+3x-4=0 are x=(-1+sqrt(17))/6 ,x=-(1+sqrt(17))/6