What are the solutions to the equation 3c^2-13c-10=0 ?

The solutions to the equation 3c^2-13c-10=0 are c=5,c=-2/3

Find the zeros of 3c^2-13c-10=0

The zeros of 3c^2-13c-10=0 are c=5,c=-2/3

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3 c^{2} - 13 c - 10 = 0

c = 5, c = - \frac{2}{3}

Decimal Notation

c = 5, c = - 0.66666 \dots

Solution steps

3 c^{2} - 13 c - 10 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

(- 13)^{2} - 4 \cdot 3 (- 10) = 17

c_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 \cdot 3}

Separate the solutions

c_{1} = \frac{- ( - 13 ) + 17}{2 \cdot 3}, c_{2} = \frac{- ( - 13 ) - 17}{2 \cdot 3}

c = \frac{- ( - 13 ) + 17}{2 \cdot 3} : 5

c = \frac{- ( - 13 ) - 17}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

c = 5, c = - \frac{2}{3}

x^{2} + x^{2}

1 - (\frac{4}{5})^{2}

p^{2} + 5 p - 24 = 0

- 5 (x + 7) < - 10

- 12 = 2 x^{2} + 2 x - 12

What are the solutions to the equation 3c^2-13c-10=0 ?
The solutions to the equation 3c^2-13c-10=0 are c=5,c=-2/3
Find the zeros of 3c^2-13c-10=0
The zeros of 3c^2-13c-10=0 are c=5,c=-2/3