p^2+5p-24=0

解

p^{2} + 5 p - 24 = 0

p = 3, p = - 8

解答ステップ

p^{2} + 5 p - 24 = 0

解くとthe二次式

p_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 24) = 11

p_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 1}

解を分離する

p_{1} = \frac{- 5 + 11}{2 \cdot 1}, p_{2} = \frac{- 5 - 11}{2 \cdot 1}

p = \frac{- 5 + 11}{2 \cdot 1} : 3

p = \frac{- 5 - 11}{2 \cdot 1} : - 8

二次equationの解:

p = 3, p = - 8