What are the solutions to the equation 5x^2+57x-36=0 ?

The solutions to the equation 5x^2+57x-36=0 are x= 3/5 ,x=-12

Find the zeros of 5x^2+57x-36=0

The zeros of 5x^2+57x-36=0 are x= 3/5 ,x=-12

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5 x^{2} + 57 x - 36 = 0

x = \frac{3}{5}, x = - 12

Decimal Notation

x = 0.6, x = - 12

Solution steps

5 x^{2} + 57 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 57 \pm 5 7 ^{2} - 4 \cdot 5 ( - 36 )}{2 \cdot 5}

5 7^{2} - 4 \cdot 5 (- 36) = 63

x_{1, 2} = \frac{- 57 \pm 63}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 57 + 63}{2 \cdot 5}, x_{2} = \frac{- 57 - 63}{2 \cdot 5}

x = \frac{- 57 + 63}{2 \cdot 5} : \frac{3}{5}

x = \frac{- 57 - 63}{2 \cdot 5} : - 12

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - 12

∣ 9 x + 2 ∣ + 4 < 6

\frac{( - 4 ) ^{8} \cdot ( - 4 ) ^{3}}{( - 4 ) ^{4} \cdot ( - 4 ) ^{2}}

\frac{- 25}{- 5}

3 x^{2} - 4 x - 15 = 0

∣ x - 6 ∣ < - 1

What are the solutions to the equation 5x^2+57x-36=0 ?
The solutions to the equation 5x^2+57x-36=0 are x= 3/5 ,x=-12
Find the zeros of 5x^2+57x-36=0
The zeros of 5x^2+57x-36=0 are x= 3/5 ,x=-12