What are the solutions to the equation 3x^2-4x-15=0 ?

The solutions to the equation 3x^2-4x-15=0 are x=3,x=-5/3

Find the zeros of 3x^2-4x-15=0

The zeros of 3x^2-4x-15=0 are x=3,x=-5/3

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3 x^{2} - 4 x - 15 = 0

x = 3, x = - \frac{5}{3}

Decimal Notation

x = 3, x = - 1.66666 \dots

Solution steps

3 x^{2} - 4 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 15) = 14

x_{1, 2} = \frac{- ( - 4 ) \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 14}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 14}{2 \cdot 3}

x = \frac{- ( - 4 ) + 14}{2 \cdot 3} : 3

x = \frac{- ( - 4 ) - 14}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{5}{3}

∣ x - 6 ∣ < - 1

b - 7 \leq 9 - 3 b

(\frac{8}{9})^{- 2}

\frac{\frac{1}{x + h} - \frac{1}{x}}{h}

x (4 - 5 x) \leq 0

What are the solutions to the equation 3x^2-4x-15=0 ?
The solutions to the equation 3x^2-4x-15=0 are x=3,x=-5/3
Find the zeros of 3x^2-4x-15=0
The zeros of 3x^2-4x-15=0 are x=3,x=-5/3