What are the solutions to the equation 4x^2+9x+5=0 ?

The solutions to the equation 4x^2+9x+5=0 are x=-1,x=-5/4

Find the zeros of 4x^2+9x+5=0

The zeros of 4x^2+9x+5=0 are x=-1,x=-5/4

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4 x^{2} + 9 x + 5 = 0

x = - 1, x = - \frac{5}{4}

Decimal Notation

x = - 1, x = - 1.25

Solution steps

4 x^{2} + 9 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

9^{2} - 4 \cdot 4 \cdot 5 = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 \cdot 4}, x_{2} = \frac{- 9 - 1}{2 \cdot 4}

x = \frac{- 9 + 1}{2 \cdot 4} : - 1

x = \frac{- 9 - 1}{2 \cdot 4} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{5}{4}

\frac{m ^{- \frac{5}{2}}}{m ^{- 2}}

4 + 2 k > 8

4 x^{2} + 3 x - 10

- x^{2} + 18 x - 81 \geq 0

\frac{2}{3} (1)^{- \frac{1}{3}}

What are the solutions to the equation 4x^2+9x+5=0 ?
The solutions to the equation 4x^2+9x+5=0 are x=-1,x=-5/4
Find the zeros of 4x^2+9x+5=0
The zeros of 4x^2+9x+5=0 are x=-1,x=-5/4