What are the solutions to the equation x^2+4x+10=0 ?

The solutions to the equation x^2+4x+10=0 are x=-2+sqrt(6)i,x=-2-sqrt(6)i

Find the zeros of x^2+4x+10=0

The zeros of x^2+4x+10=0 are x=-2+sqrt(6)i,x=-2-sqrt(6)i

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x^{2} + 4 x + 10 = 0

x = - 2 + 6 i, x = - 2 - 6 i

Solution steps

x^{2} + 4 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 10 : 26 i

x_{1, 2} = \frac{- 4 \pm 2 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 6 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 6 i}{2 \cdot 1}

x = \frac{- 4 + 2 6 i}{2 \cdot 1} : - 2 + 6 i

x = \frac{- 4 - 2 6 i}{2 \cdot 1} : - 2 - 6 i

The solutions to the quadratic equation are:

x = - 2 + 6 i, x = - 2 - 6 i

\frac{x y ^{9}}{3 y ^{- 2}} \cdot \frac{- 7 y}{21 x ^{5}}

4 (6 + 2 x) + 3 \geq 9 - x

(\frac{2}{5} m^{4} n + \frac{1}{3} mn) (\frac{3}{2} m^{2} n + 2 mn - 3)

7 x - 10 = 5 x + 8

5 x + 2 = - 16

What are the solutions to the equation x^2+4x+10=0 ?
The solutions to the equation x^2+4x+10=0 are x=-2+sqrt(6)i,x=-2-sqrt(6)i
Find the zeros of x^2+4x+10=0
The zeros of x^2+4x+10=0 are x=-2+sqrt(6)i,x=-2-sqrt(6)i