What is (xy^9)/(3y^{-2)}*(-7y)/(21x^5) ?

The solution to (xy^9)/(3y^{-2)}*(-7y)/(21x^5) is -(y^{12})/(9x^4)

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simplify (xy^9)/(3y^{-2)}*(-7y)/(21x^5)

simplify

\frac{x y ^{9}}{3 y ^{- 2}} \cdot \frac{- 7 y}{21 x ^{5}}

- \frac{y ^{12}}{9 x ^{4}}

Solution steps

\frac{x y ^{9}}{3 y ^{- 2}} \cdot \frac{- 7 y}{21 x ^{5}}

Cancel

\frac{x y ^{9}}{3 y ^{- 2}} : \frac{x y ^{11}}{3}

= \frac{x y ^{11}}{3} \cdot \frac{- 7 y}{21 x ^{5}}

Cancel

\frac{- 7 y}{21 x ^{5}} : - \frac{y}{3 x ^{5}}

= \frac{x y ^{11}}{3} (- \frac{y}{3 x ^{5}})

Apply rule:

a (- b) = - ab

\frac{x y ^{11}}{3} (- \frac{y}{3 x ^{5}}) = - \frac{x y ^{11}}{3} \cdot \frac{y}{3 x ^{5}}

= - \frac{x y ^{11}}{3} \cdot \frac{y}{3 x ^{5}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= - \frac{x y ^{11} y}{3 \cdot 3 x ^{5}}

Simplify

\frac{x}{x ^{5}} : \frac{1}{x ^{4}}

= - \frac{y ^{11} y}{3 \cdot 3 x ^{4}}

Simplify

y^{11} y : y^{12}

= - \frac{y ^{12}}{3 \cdot 3 x ^{4}}

Multiply the numbers:

3 \cdot 3 = 9

= - \frac{y ^{12}}{9 x ^{4}}

4 (6 + 2 x) + 3 \geq 9 - x

(\frac{2}{5} m^{4} n + \frac{1}{3} mn) (\frac{3}{2} m^{2} n + 2 mn - 3)

7 x - 10 = 5 x + 8

5 x + 2 = - 16

\frac{5 m ^{- 1}}{9 ( ab ) ^{- 4} c ^{7}}

What is (xy^9)/(3y^{-2)}*(-7y)/(21x^5) ?
The solution to (xy^9)/(3y^{-2)}*(-7y)/(21x^5) is -(y^{12})/(9x^4)