What is [(x^2y^{-2})^{-1}] ?

The solution to [(x^2y^{-2})^{-1}] is (y^2)/(x^2)

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simplify [(x^2y^{-2})^{-1}]

simplify

[(x^{2} y^{- 2})^{- 1}]

\frac{y ^{2}}{x ^{2}}

Solution steps

(x^{2} y^{- 2})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(x^{2} y^{- 2})^{- 1} = \frac{1}{x ^{2} y ^{- 2}}

= \frac{1}{x ^{2} y ^{- 2}}

Multiply

x^{2} y^{- 2} : \frac{x ^{2}}{y ^{2}}

= \frac{1}{\frac{x ^{2}}{y ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{2}}{x ^{2}}

x^{2} + 2 = 0

(a^{2} - 1) b^{2} - 4 (a^{2} - 1)

45 x^{2} - 25 y^{2}

(2 k - 1)^{2} - (k + 5)^{2}

3 x^{2} - 7 x - 8 = 0