What are the solutions to the equation x^2+2=0 ?

The solutions to the equation x^2+2=0 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of x^2+2=0

The zeros of x^2+2=0 are x=sqrt(2)i,x=-sqrt(2)i

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x^{2} + 2 = 0

x = 2 i, x = - 2 i

Solution steps

x^{2} + 2 = 0

Move

2

to the right side

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

(a^{2} - 1) b^{2} - 4 (a^{2} - 1)

45 x^{2} - 25 y^{2}

(2 k - 1)^{2} - (k + 5)^{2}

3 x^{2} - 7 x - 8 = 0

2 x^{2} - 6 x + 14 = 0

What are the solutions to the equation x^2+2=0 ?
The solutions to the equation x^2+2=0 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of x^2+2=0
The zeros of x^2+2=0 are x=sqrt(2)i,x=-sqrt(2)i