What is factor 4p^2-28p+49 ?

The solution to factor 4p^2-28p+49 is (2p-7)^2

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factor 4p^2-28p+49

factor

4 p^{2} - 28 p + 49

(2 p - 7)^{2}

Solution steps

4 p^{2} - 28 p + 49

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 p^{2} = (2 p)^{2}

49 = 7^{2}

- 28 p = - 2 \cdot 2 p \cdot 7

= (2 p)^{2} - 2 \cdot 2 p \cdot 7 + 7^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(2 p)^{2} - 2 \cdot 2 p \cdot 7 + 7^{2} = (2 p - 7)^{2}

= (2 p - 7)^{2}

\frac{1 - \frac{1}{16}}{\frac{1}{16}}

5^{\frac{5}{2}}

(\frac{a ^{3}}{5 m})^{- 4}

x + 6 < 5 x - 6

x^{2} - 9 = x + 11