What are the solutions to the equation x^2+3x-54=0 ?

The solutions to the equation x^2+3x-54=0 are x=6,x=-9

Find the zeros of x^2+3x-54=0

The zeros of x^2+3x-54=0 are x=6,x=-9

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x^{2} + 3 x - 54 = 0

x = 6, x = - 9

Solution steps

x^{2} + 3 x - 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 54 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 54) = 15

x_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 15}{2 \cdot 1}, x_{2} = \frac{- 3 - 15}{2 \cdot 1}

x = \frac{- 3 + 15}{2 \cdot 1} : 6

x = \frac{- 3 - 15}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 6, x = - 9

\frac{\frac{1}{10}}{2}

9^{3}

3 x^{2} - 3 x - 9

(\frac{1}{x + 1})^{2}

4 m n^{2} - 4 m^{2} n^{2} + m^{3} n^{2}

What are the solutions to the equation x^2+3x-54=0 ?
The solutions to the equation x^2+3x-54=0 are x=6,x=-9
Find the zeros of x^2+3x-54=0
The zeros of x^2+3x-54=0 are x=6,x=-9