What are the solutions to the equation (2x-5)^2=-12 ?

The solutions to the equation (2x-5)^2=-12 are x= 5/2+sqrt(3)i,x= 5/2-sqrt(3)i

Find the zeros of (2x-5)^2=-12

The zeros of (2x-5)^2=-12 are x= 5/2+sqrt(3)i,x= 5/2-sqrt(3)i

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(2 x - 5)^{2} = - 12

x = \frac{5}{2} + 3 i, x = \frac{5}{2} - 3 i

Solution steps

(2 x - 5)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 5 = - 12 : x = \frac{5}{2} + 3 i

Solve

2 x - 5 = - - 12 : x = \frac{5}{2} - 3 i

The solutions to the quadratic equation are:

x = \frac{5}{2} + 3 i, x = \frac{5}{2} - 3 i

8^{- \frac{5}{3}}

3 v = 24

2 (x - 2) + x = 5

x^{2} + 2 x + 1 = x + 1

x^{3} - 5 x^{2} - 3 x + 15

What are the solutions to the equation (2x-5)^2=-12 ?
The solutions to the equation (2x-5)^2=-12 are x= 5/2+sqrt(3)i,x= 5/2-sqrt(3)i
Find the zeros of (2x-5)^2=-12
The zeros of (2x-5)^2=-12 are x= 5/2+sqrt(3)i,x= 5/2-sqrt(3)i