What are the solutions to the equation x^2+2x+1=x+1 ?

The solutions to the equation x^2+2x+1=x+1 are x=0,x=-1

Find the zeros of x^2+2x+1=x+1

The zeros of x^2+2x+1=x+1 are x=0,x=-1

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x^{2} + 2 x + 1 = x + 1

x = 0, x = - 1

Solution steps

x^{2} + 2 x + 1 = x + 1

Move

1

to the left side

x^{2} + 2 x = x

Move

x

to the left side

x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 1}, x_{2} = \frac{- 1 - 1}{2 \cdot 1}

x = \frac{- 1 + 1}{2 \cdot 1} : 0

x = \frac{- 1 - 1}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

x^{3} - 5 x^{2} - 3 x + 15

3 x^{2} - 5 = 0

x^{2} - 6 x y - 16 y^{2}

- (- 2 - n)

\frac{6 - x}{x - 5} \geq - 3

What are the solutions to the equation x^2+2x+1=x+1 ?
The solutions to the equation x^2+2x+1=x+1 are x=0,x=-1
Find the zeros of x^2+2x+1=x+1
The zeros of x^2+2x+1=x+1 are x=0,x=-1