faktorisieren 1/64 x^2-4/81

Lösung

faktorisieren

\frac{1}{64} x^{2} - \frac{4}{81}

(\frac{1}{8} x + \frac{2}{9}) (\frac{1}{8} x - \frac{2}{9})

Schritte zur Lösung

\frac{1}{64} x^{2} - \frac{4}{81}

\frac{1}{64} x^{2} = (\frac{1}{8} x)^{2}

\frac{4}{81} = (\frac{2}{9})^{2}

= (\frac{1}{8} x)^{2} - (\frac{2}{9})^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(\frac{1}{8} x)^{2} - (\frac{2}{9})^{2} = (\frac{1}{8} x + \frac{2}{9}) (\frac{1}{8} x - \frac{2}{9})

= (\frac{1}{8} x + \frac{2}{9}) (\frac{1}{8} x - \frac{2}{9})

\frac{x + 3}{x + 8} < \frac{x - 1}{x - 3}

f a c t or 2 x^{3} - 20 x^{2} - 48 x

f a c t or x^{3} + 125 y^{3}

- \frac{1}{2} x^{2} = - 6 x + 20

s im pl i f y (3 x^{\frac{1}{2}}) (4 x^{\frac{2}{3}})