What are the solutions to the equation 0=4x^2-x ?

The solutions to the equation 0=4x^2-x are x= 1/4 ,x=0

Find the zeros of 0=4x^2-x

The zeros of 0=4x^2-x are x= 1/4 ,x=0

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0 = 4 x^{2} - x

x = \frac{1}{4}, x = 0

Decimal Notation

x = 0.25, x = 0

Solution steps

0 = 4 x^{2} - x

Switch sides

4 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 4}

x = \frac{- ( - 1 ) + 1}{2 \cdot 4} : \frac{1}{4}

x = \frac{- ( - 1 ) - 1}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 0

0 = x^{2} - 4 x + 1

3 + \frac{3}{2}

∣ x - 6 ∣ \leq 5

ln (e^{5})

6 x^{2} + 18 x - 108

What are the solutions to the equation 0=4x^2-x ?
The solutions to the equation 0=4x^2-x are x= 1/4 ,x=0
Find the zeros of 0=4x^2-x
The zeros of 0=4x^2-x are x= 1/4 ,x=0