What are the solutions to the equation λ^2+1=0 ?

The solutions to the equation λ^2+1=0 are λ=i,λ=-i

Find the zeros of λ^2+1=0

The zeros of λ^2+1=0 are λ=i,λ=-i

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λ^{2} + 1 = 0

λ = i, λ = - i

Solution steps

λ^{2} + 1 = 0

Move

1

to the right side

λ^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

λ = - 1, λ = - - 1

- 1 = i

- - 1 = - i

λ = i, λ = - i

- \frac{5}{4} + \frac{75}{40} + 100%

x + 8 = - 4

11 x (2 x - 5)^{- \frac{1}{4}} - 7 (2 x - 5)^{\frac{3}{4}}

9 x^{2} - 8 x

x^{2} + 10 x + 74 = 0

What are the solutions to the equation λ^2+1=0 ?
The solutions to the equation λ^2+1=0 are λ=i,λ=-i
Find the zeros of λ^2+1=0
The zeros of λ^2+1=0 are λ=i,λ=-i