What is (49m^4n-21m^6n^2)/(7m^2n^4) ?

The solution to (49m^4n-21m^6n^2)/(7m^2n^4) is (m^2(7-3m^2n))/(n^3)

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simplify (49m^4n-21m^6n^2)/(7m^2n^4)

simplify

\frac{49 m ^{4} n - 21 m ^{6} n ^{2}}{7 m ^{2} n ^{4}}

\frac{m ^{2} ( 7 - 3 m ^{2} n )}{n ^{3}}

Solution steps

\frac{49 m ^{4} n - 21 m ^{6} n ^{2}}{7 m ^{2} n ^{4}}

Factor

49 m^{4} n - 21 m^{6} n^{2} : 7 m^{4} n (7 - 3 m^{2} n)

= \frac{7 m ^{4} n ( 7 - 3 m ^{2} n )}{7 m ^{2} n ^{4}}

Cancel the common factor:

7

= \frac{m ^{4} n ( 7 - 3 m ^{2} n )}{m ^{2} n ^{4}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

m^{4} = m^{2} m^{2}

= \frac{m ^{2} m ^{2} n ( 7 - 3 m ^{2} n )}{m ^{2} n ^{4}}

Cancel the common factor:

m^{2}

= \frac{m ^{2} n ( 7 - 3 m ^{2} n )}{n ^{4}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

n^{4} = n n^{3}

= \frac{m ^{2} n ( 7 - 3 m ^{2} n )}{n n ^{3}}

Cancel the common factor:

n

= \frac{m ^{2} ( 7 - 3 m ^{2} n )}{n ^{3}}

6 x^{2} + 4 x - 3 \geq 0

\frac{1}{4} x - 3 \geq - 1

p^{2} + 3 p - 18

\frac{1}{( \frac{11}{2} )}

λ^{2} + 1 = 0

What is (49m^4n-21m^6n^2)/(7m^2n^4) ?
The solution to (49m^4n-21m^6n^2)/(7m^2n^4) is (m^2(7-3m^2n))/(n^3)