What are the solutions to the equation (x+4)^2=0 ?

The solutions to the equation (x+4)^2=0 are x=-4

Find the zeros of (x+4)^2=0

The zeros of (x+4)^2=0 are x=-4

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(x + 4)^{2} = 0

x = - 4

Solution steps

(x + 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x + 4 = 0 : x = - 4

The solution to the quadratic equation is:

x = - 4

x < 1 and x > - 4

4 x + 6 = 2 + 3 (x + 2)

2 x^{2} - 4 x + 12

\frac{20 x ^{8} y}{30 x ^{3} y ^{5}}

0 = 6 x^{2} + 6 x - 12

What are the solutions to the equation (x+4)^2=0 ?
The solutions to the equation (x+4)^2=0 are x=-4
Find the zeros of (x+4)^2=0
The zeros of (x+4)^2=0 are x=-4